`3x - 5y = 8, 2x + 5y = 22` Solve the system by the method of substitution.

3x-5y=8     2x+5y=22

Solve second equation for x; first subtract 5y from each side.

2x=-5y+22    Divide by 2

x=-5/2y+11   Then substitute into x into the first equation

3 (-5/2y+11)-5y=8   Simplify

-15/2y +33-5y=8    Combine like terms

-25/2y+ 33=8   -25/2y=-25  Divide each side by -25

1/2y=1    y=2    Therefore 3x-5(2)=8   3x-10=8   3x=18   x=6

x=6, y=2      They check in both equations.

3x-5y=8     2x+5y=22

Solve second equation for x; first subtract 5y from each side.

2x=-5y+22    Divide by 2

x=-5/2y+11   Then substitute into x into the first equation

3 (-5/2y+11)-5y=8   Simplify

-15/2y +33-5y=8    Combine like terms

-25/2y+ 33=8   -25/2y=-25  Divide each side by -25

1/2y=1    y=2    Therefore 3x-5(2)=8   3x-10=8   3x=18   x=6

x=6, y=2      They check in both equations.