To solve this, assume that the three consecutive numbers are all integers. Then, assign a variable that represents the first integer. Let it be x. So the next two integers are x+1 and x+2.
Then, add these three integers and set it equal to the given sum.
`x + (x+1)+(x+2)=93`
And solve for x.
`3x+3=93`
`3x=93-3`
`3x=90`
`x=90/3`
`x=30`
This is the first integer. The other two integers are:
second integer `= x + 1...
To solve this, assume that the three consecutive numbers are all integers. Then, assign a variable that represents the first integer. Let it be x. So the next two integers are x+1 and x+2.
Then, add these three integers and set it equal to the given sum.
`x + (x+1)+(x+2)=93`
And solve for x.
`3x+3=93`
`3x=93-3`
`3x=90`
`x=90/3`
`x=30`
This is the first integer. The other two integers are:
second integer `= x + 1 = 30+1 = 31`
third integer `= x+2=30+2=32`
Therefore, the three consecutive numbers that add up to 93 are 30, 31 and 32.
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