Well, the first part of the question is easy. If the firecracker was thrown at a speed of 30 meters per second, then the firecracker exploded at 15 meters, it was in the air for half a second, or .5 seconds. That can be calculated like this
15 meters divided by 30 meters/second = .5 seconds, or half a second.
The second part of the question is a little harder. To throw at an angle...
Well, the first part of the question is easy. If the firecracker was thrown at a speed of 30 meters per second, then the firecracker exploded at 15 meters, it was in the air for half a second, or .5 seconds. That can be calculated like this
15 meters divided by 30 meters/second = .5 seconds, or half a second.
The second part of the question is a little harder. To throw at an angle of 100 degrees, that would be a 10 degree angle from the vertical measurement. If we extend a line straight down from the end of the firecracker's journey, we can do a scale measurement to determine the second line, which would be the height of the firecracker off the ground.
15 meter hypotenuse, If we draw it to scale, with 1 centimeter equaling one meter, that would produce a 2.5 meter distance for the base of the triangle, away from the vertical. Then, using the pythagorean theorem, where c2 = a2 + b2:
225 = 6.25 + b2
225 - 6.25 = 6.25 - 6.25 + b2
218.75 = b2
14.79 meters = b, which would represent the height above the ground the firecracker traveled to before exploding.
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