Saturday, April 6, 2013

`-x + 3y = 17, 4x + 3y = 7` Use any method to solve the system.

EQ1:  `-x+3y=17`


EQ2:  `4x+3y=7`


To solve this system of equation, let's apply substitution method. To do so,  isolate the x in the first equation.


`-x+3y=17`


`-x=17-3y`


`x=(17-3y)/(-1)`


`x=-17 + 3y`


Then, plug-in this to the second equation. 


`4x+3y=7`


`4(-17+3y)+3y=7`


And, solve for y.


`-68+15y=7`


`15y=7+68`


`15y=75`


`y=75/15`


`y=5`


Now that the value of y is known, solve for x. Plug-in y = 5 to the first equation.


`-x+3y=17`


`-x+3(5)=17`


`-x+15=17`


`-x=17-15`


`-x=2`


`x=2/(-1)`


`x=-2`


Therefore,...

EQ1:  `-x+3y=17`


EQ2:  `4x+3y=7`


To solve this system of equation, let's apply substitution method. To do so,  isolate the x in the first equation.


`-x+3y=17`


`-x=17-3y`


`x=(17-3y)/(-1)`


`x=-17 + 3y`


Then, plug-in this to the second equation. 


`4x+3y=7`


`4(-17+3y)+3y=7`


And, solve for y.



`-68+15y=7`


`15y=7+68`


`15y=75`


`y=75/15`


`y=5`


Now that the value of y is known, solve for x. Plug-in y = 5 to the first equation.


`-x+3y=17`


`-x+3(5)=17`


`-x+15=17`


`-x=17-15`


`-x=2`


`x=2/(-1)`


`x=-2`


Therefore, the solution is (-2,5).

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