`f(x) = 2 sin(x) - sin(2x), [0, pi]` Find the average value of the function on the given interval.

The average value on an interval is the integral on this interval divided by the length of the interval.

The length is `pi` . The integral is

`(-2cos(x)+1/2 cos(2x))|_0^pi=2+1/2+2-1/2=4.`

So the average value is `4/pi.`

The average value on an interval is the integral on this interval divided by the length of the interval.

The length is `pi` . The integral is

`(-2cos(x)+1/2 cos(2x))|_0^pi=2+1/2+2-1/2=4.`

So the average value is `4/pi.`