Monday, November 14, 2016

A cylindrical centrifuge of mass 8 kg and radius 10 cm spins at a speed of 80,000 rpm. Calculate the minimum braking torque that must be applied...

Hello!


I suppose we apply a constant braking force perpendicularly to the radius of spin. Then the torque (moment of force) will be


From the other hand, this torque will cause an angular acceleration (deceleration in this case) and the relation between them is


where is the moment of inertia of a centrifuge.



For an object whose mass is at the constant distance from the axis of rotation,...

Hello!


I suppose we apply a constant braking force perpendicularly to the radius of spin. Then the torque (moment of force) will be


From the other hand, this torque will cause an angular acceleration (deceleration in this case) and the relation between them is


where is the moment of inertia of a centrifuge.



For an object whose mass is at the constant distance from the axis of rotation, the moment of inertia is  Linking this together, obtain


or



The angular speed will decrease uniformly at a rate A centrifuge stops when so where is the initial angular speed and is the given time of braking.



Finally, all these quantities are given. The only problem is that is given in rpm, while it is required in radians per second. One rpm is radians per second, so the final answer is




This is the braking force. The torque itself is

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